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For a body starting from rest what will be the ratio of the distance travelled by the body the 4th and 3rd second during its journey.
Distance travelled by a body in nth second. A boy travels a distance of 3km towards east then 4km towards north and finally 9km towards east. The distance travelled is the area of the shaded portion. The Formula to calculate the distance travelled by a body in Nth second is given by This is the Fourth Equation of Motion.
U initial velocity of body A Acceleration----- thanks Shubhendu8898 Shubhendu8898 Given let Initial velocity of an object is u and acceleration is a. Asked by Priyank Mahajan 28th Jun 2012 0737. Displacement of Particle in nth Second.
S ut. If the body is moving at constant velocity the distance traveled is simply the velocity multiplied by one secondThis is the formula given in a lot of the answers. A stone falls freely such that the distance covered by it in the last second of its motion is equal to the distance covered by it in the first 5 seconds.
Best answer The distance covered by a body in nth second can be found by subtracting the distance covered by a body in n - 1 second from the distance covered by the body in n second. Also find its velocity at the end of 2 seconds. It covers as much distance in the last second of its motion as covered in the first three seconds.
Expression for the Distance Travelled by Body in nth Second of its Motion. Let the displacement of the particle in the nth second of its motion be Snth. By Newtons Second equation of motion s ut ½ at² where s displacement of body in t seconds u initial velocity of the body a acceleration of the body t time.
Find the initial velocity and acceleration. Derive an equation for the distance travelled by a uniformly accelerated body in nth second of its motion. Snth Sn - sn-1 When Sn and Sn-1 are displacements are the particle in n and n-1 seconds.
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