First Class Work Done By Gravity

Given that work done on a body equals zero when either the displacement or net force on the body is zero this non-force view of gravity implies work done by gravity is also technically zero.

Work done by gravity. Was this answer helpful. Work Done Examples Positive Work. A typical coordinate system has the x -axis horizontal and the y.

And not you are not correct to think that stationary object is the same as zero work done by gravity. In other words a body in a gravitational field follows its geodesic without the need for a force dragging it along. If a force relocates the object in its direction then the work done is positive.

Therefore since the force is gravity and it points down the displacement of the box in the direction of that force is only the vertical distance or height. No change in speed of the object - no change in KE - no total work done on it. Work done by gravity Formula If you apply a force on a moving object we say that the force you are exerting performs a work.

The example of this type of work done is the motion of the ball dropping towards the ground where the displacement of the ball is in the direction of the force of gravity. Work against gravity mass acceleration due to gravityheight. This feature of motion when end conditions are same facilitates computation of work by other forces a great deal as we need not be concerned of the external force other than gravity.

The work done by air resistance doesnt depend on the force of gravity etc. If the angle between gravitational force and direction of motion is 𝚹 then work done due to gravity is given by W mgh cos 𝚹 So if an object is moving in horizontal direction on the surface of earth then work done by gravity is zero. The simple answer is the dot product of force and displacement.

And the definition of work done is the force multiplied by the displacement that is in the direction of that force. If a particular object is falling the particle is bound to point in the direction of gravity. In many cases it is convenient to express the dot product for gravitational work in terms of the x - y - and z -components of the vectors.